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Home/ Questions/Q 975107
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:31:55+00:00 2026-05-16T03:31:55+00:00

my form <form action= method=post> <p>Shirt 1 : <input type=radio name=myradio id=myradio value=0/></p> <p>Shirt

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my form

<form action="" method="post">

<p>Shirt 1 : <input type="radio" name="myradio" id="myradio" value="0"/></p>
<p>Shirt 2 : <input type="radio" name="myradio" id="myradio"  value="1"/></p>


<input type="button" name="submit" id="submit" value="create" onclick="createImage()" />

</form>

my javascript:

function createImage(){

     $.ajax({


        type: "POST",
        url: "output.php",
        data:   "myradio=" + document.getElementById("myradio").value,
        success: function(html){
            $("#output").html(html);
        }   


     });
}

for $_POST['myradio'] I’m only getting the value of 0 even if I click the 2nd radio button. Do I need to give the radio buttons different id’s?

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:31:56+00:00Added an answer on May 16, 2026 at 3:31 am

    use :checked selector. This will give you the checked radio button. Also, IDs should be unique in a page. My example here uses class myradio.

    data:   "myradio=" + $(".myradio:checked").val(),
    

    another elegant way is to use .serialize(). This will give you the string param for submission.

    in your example, if we use .serialize(), we can get something like myradio=0 if myradio with a value of zero is checked.

    sample code, try it here

    $(function(){
        $(':button').click(function() {
            alert($('form').serialize());
            return false;
        });
    });
    ​
    
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