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Home/ Questions/Q 3999994
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T07:43:37+00:00 2026-05-20T07:43:37+00:00

My implementation of flatten looks like this: (define flatten (lambda (lst) (if (null? lst)

  • 0

My implementation of flatten looks like this:

(define flatten
  (lambda (lst)
    (if (null? lst)
        lst
        (append
          (rtn-lst (car lst))
          (flatten (cdr lst))))))

(define rtn-lst
  (lambda (lst)
    (cond 
      ((null? lst) 
        empty)
      ((atom? lst)
        (list lst))
      (else 
        (flatten lst)))))

While standard implementation is:

(define (flatten lst)
  (cond 
    ((null? list)
      empty)
    ((list? (car lst))
      (append (flatten (car lst)) (flatten (cdr lst))))
    (else
      (cons (car lst) (flatten (cdr lst))))))

Apart from the obvious verboseness, what else is wrong with my code?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T07:43:37+00:00Added an answer on May 20, 2026 at 7:43 am

    I’d try this:

    (define rtn-lst
      (lambda (lst)
        (cond 
          ((list? lst)
            (if (null? lst)
                empty
                (flatten-list lst)))
          ((atom? lst)
            (list lst))
          (else 
            (flatten-list lst)))))
    

    Probably we have different implementations of Scheme.

    EDIT:

    With modified else branch:

    (define rtn-lst
      (lambda (lst)
        (cond 
          ((list? lst)
            (if (null? lst)
                empty
                (flatten-list lst)))
          (else 
            (list lst)))))
    
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