Question

My int values:

    int a= 0x02; int b= 1; int c= 2; int d = 0; int e = 0; int f = 0; int g= 1;

How can I concatenate these integers and get a single int value?
and the result int value should have first 8 bits for “a” and 4 bits each for the rest??

Something like : 2120001

Answer 1

int a= 0x02; int b= 1; int c= 2; int d = 0; int e = 0; int f = 0; int g= 1;
int res=((a&0xff)<<24)|((b&0xf)<<20)|((c&0xf)<<16)
       |((d&0xf)<<12)|((e&0xf)<<8)|((f&0xf)<<4)|((g&0xf));
System.out.println(Integer.toHexString(res));

Yields:
2120001