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Home/ Questions/Q 8723647
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T07:40:26+00:00 2026-06-13T07:40:26+00:00

My interpretation of _._1 is: _ = wildcard parameter _1 = first parameter in

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My interpretation of _._1 is:

_ = wildcard parameter
_1 = first parameter in method parameter list
But when used together with . what does it signify?

This is how its used :

.toList.sortWith(_._1 < _._1)

For this statement:

_++_

I’m lost. Is it concatenation two wildcard parameters somehow?
This is how its used:

.reduce(_++_)

I would be particularly interested if they above code could be made more verbose and remove any implicits, just so I can understand it better?

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  1. Editorial Team
    Editorial Team
    2026-06-13T07:40:27+00:00Added an answer on June 13, 2026 at 7:40 am

    _._1 calls the method _1 on the wildcard parameter _, which gets the first element of a tuple. Thus, sortWith(_._1 < _._1) sorts the list of tuple by their first element.

    _++_ calls the method ++ on the first wildcard parameter with the second parameter as an argument. ++ does concatenation for sequences. Thus .reduce(_++_) concatenates a list of sequences together. Usually you can use flatten for that.

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