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Home/ Questions/Q 9122817
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T06:11:32+00:00 2026-06-17T06:11:32+00:00

my ip field in the mysql database is VARBINARY(16) // Insert into website table

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my ip field in the mysql database is VARBINARY(16)

  // Insert into website table
    $ip = inet_pton('::1'); // Local ip
    $data_rec = array(
            'ip_address' => $ip,
            );  
    $this->db->insert('visitors', $data_rec); 

The ip doesn’t get inserted. It’s a blank field. Why is that?

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  1. Editorial Team
    Editorial Team
    2026-06-17T06:11:33+00:00Added an answer on June 17, 2026 at 6:11 am

    inet_pton() returns unprintable characters.
    Did you try to read it from the database and do echo inet_topn()?

    Given that I have a table

    CREATE TABLE `ip` (
      `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
      `ip` varbinary(16) DEFAULT NULL,
      PRIMARY KEY (`id`)
    )
    

    And using this simple script (all checks intentionally omitted for simplicity)

    <?php
    $in6_addr = inet_pton('::1');
    
    $db = new mysqli('localhost', '******', '******', 'test');
    
    $qry = "INSERT INTO ip (ip) VALUES('$in6_addr')";
    $db->query($qry));
    
    $qry = "SELECT * FROM ip WHERE id=1";
    $result = $db->query($qry);
    if ($row = $result->fetch_array(MYSQL_ASSOC)) {
        echo inet_ntop($row['ip']);
    }    
    ?>
    

    you get the output

    ::1
    

    But you can’t see the value in phpAdmin or Sequel Pro

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