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Home/ Questions/Q 4233820
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T02:16:08+00:00 2026-05-21T02:16:08+00:00

My iPhone has a line of code that looks like this: double decimal2 =

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My iPhone has a line of code that looks like this:

double decimal2 = abs(newLocation.coordinate.longitude - degrees);

I’m trying to ensure that the value of decimal2 is always positive. However, decimal2 is currently -82.

Can anyone explain this? I’m not doing anything else to the value of decimal2.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-21T02:16:09+00:00Added an answer on May 21, 2026 at 2:16 am

    would suggest you to use NSDecimalNumber

    You could use the built-in functions of the NSDecimalNumber class to compare the number to zero, then multiply by -1 as appropriate. For example:

    - (NSDecimalNumber *)abs:(NSDecimalNumber *)num {
        if [myNumber compare:[NSDecimalNumber zero]] == NSOrderedAscending) {
            // Number is negative. Multiply by -1
            NSDecimalNumber * negativeOne = [NSDecimalNumber decimalNumberWithMantissa:1
                                                                              exponent:0
                                                                            isNegative:YES];
            return [num decimalNumberByMultiplyingBy:negativeOne];
        } else {
            return num;
        }
    }
    

    in this case , there’s no loss of precision

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