Question

My js:

$('#select').change(function() {
    var name = $(this).val();
    $.ajax({
        type: "POST",
        url: "data/grab.php",
        data: { type: "hops", name: name },
        dataType: "json",
        success: function(data) {
                    alert(data);
            var aa = data['aa'];
            $('#hops-aa').val(aa);
        }
    });
});

grab.php

<?php

$type = $_POST['type'];
$name = $_POST['name'];

if ($type == 'hops') {
    $result = $name;
}

$result = json_encode($result);
return $result;

I added the alert() in the ajax call to double check what I’m getting back from the script, and it’s always null. Anything I’m missing?

Answer 1

You need to actually echo or print the $result. In PHP using return from the file scope does not send the returned value to the output stream.