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Editorial Team
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Asked: 2026-05-16T02:01:59+00:00

My JSP-application requires some configuration; so I created the Settings class which is a

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My JSP-application requires some configuration; so I created the Settings class which is a wrapper to an apache commons Configuration object which should be initialized in the static constructor of Settings and I wish to do that using path to the property file. But how can I get the application path (not web path) outside the JSP page? I know that there is config auto variable in JSPs, but I need the path outside from JSP code.

This problem seems to be quite common but I’m a newbie in the java world and can’t get the solution.

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1 Answer

  1. Editorial Team

    This is indeed a bad idea and recipe for portability trouble. The common JSP/Servlet practice is to just put the file in the classpath or add its path to the classpath and obtain it as follows:

    ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
URL resource = classLoader.getResource("config.properties");
File file = new File(resource.getPath());
// ...

    or

    InputStream input = classLoader.getResourceAsStream("config.properties");
// ...

    Note that you’d like to do this in a real Java class, not in a JSP file. I can suggest the ServletContextListener for this. Use contextInitialized() method to hook on webapp’s startup.

    See also:

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