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Home/ Questions/Q 7925965
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T18:31:49+00:00 2026-06-03T18:31:49+00:00

my language is python the input looks something like: ‘0 0 0 0 1

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my language is python

the input looks something like:

'0 0 0 0 1 0 0 0 1 1 0 0' 

and so on.

i want the output:

('0 0 0 0', '1 0 0 0', '1 1 0 0') 

or every set of 4 numbers in is its own element

so far i have put together

>>> truth = re.compile('(([0-1]\D*?){4})*')
>>> truth.search('0 0 0 0 1 0 0 0').groups()
('0 0 0 0', '0')

or and several similar things but nothing is getting closer. a few things here are new to me and i’m reading the docs but can’t seem to piece together whats falling apart. Notable i don’t now why i get that last 0…

the input will eventually be many many lines but if it works for small case i’m sure it will translate over.

thanks

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  1. Editorial Team
    Editorial Team
    2026-06-03T18:31:51+00:00Added an answer on June 3, 2026 at 6:31 pm

    I wouldn’t use a regular expression for this. Instead use grouper from the recipes on the itertools documentation:

    >>> [' '.join(x) for x in grouper(4, truth.split())]
    

    See it working online: ideone


    Here’s the source code for grouper (copied from the itertools documentation):

    from itertools import izip_longest
    
    def grouper(n, iterable, fillvalue=None):
        "grouper(3, 'ABCDEFG', 'x') --> ABC DEF Gxx"
        args = [iter(iterable)] * n
        return izip_longest(fillvalue=fillvalue, *args)
    
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