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Home/ Questions/Q 7927567
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T19:22:28+00:00 2026-06-03T19:22:28+00:00

My method returns in many points. I construct newData during execution also in many

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My method returns in many points. I construct newData during execution also in many points. Regardless of where I return I need to save and store constructed result. Not to miss “return” I just surrounded the code with try-finally block so now I’m sure that newData will be stored.

List<X> newData = new List<X>();
try
{
    ....
    update newData
    .....
    return;
    .....
    ....
    update newData
    ....
    update newData
    return;
    .....
    return;
} finally
{
    // copy newData to data    
}

But I don’t catch any exceptions and this code is not intended to work with exceptions. Is it acceptable in general or you can suggest another better approach?

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  1. Editorial Team
    Editorial Team
    2026-06-03T19:22:31+00:00Added an answer on June 3, 2026 at 7:22 pm

    I would suggest refactoring the code within the try block into a new method:

    data = CreateList();
    
    ...
    
    private List<X> CreateList()
    {
        List<X> list = new List<X>();
        // It's fine to return list from any point here...
    }
    
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