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Home/ Questions/Q 6564027
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T13:54:57+00:00 2026-05-25T13:54:57+00:00

My object template , which is deserialized from a hand made XML file contains

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My object template, which is deserialized from a hand made XML file contains mixed types and the text can contain line jumps. When I look at the text I can see line jumps are \r\n, but in my deserialized template object, line jumps are \n. How can I keep line jumps as \r\n?

XmlReaderSettings settings = new XmlReaderSettings();
settings.CloseInput = true;
//settings.ValidationEventHandler += ValidationEventHandler;

settings.ValidationType = ValidationType.Schema;
settings.Schemas.Add(schema);

StringReader r = new StringReader(syntaxEdit.Text);

Schema.template rawTemplate = null;

using (XmlReader validatingReader = XmlReader.Create(r, settings))
{
    try
    {
        XmlSerializer serializer = new XmlSerializer(typeof(Schema.template));
        rawTemplate = serializer.Deserialize(validatingReader) as Schema.template;
    }
    catch (Exception ex)
    {
        rawTemplate = null;
        string floro = ex.Message + (null != ex.InnerException ? ":\n" + ex.InnerException.Message : "");
        MessageBox.Show(floro);
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-25T13:54:57+00:00Added an answer on May 25, 2026 at 1:54 pm

    It seems that this is required behavior by the XML specification and is a “feature” in Microsoft’s implementation of the XmlReader (see this answer).

    Probably the easiest thing for you to do would be to replace \n with \r\n in your result.

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