Question

My original code looks like this:

class a{
...
char buff[10];
}

and im attempting to make this change to the code:

template <int N = 10>
class a{
...
char buff[N];
}

Is there any thing I can do to keep my existing code creating instances of class a like this:

a test;

instead of making the change to:

a<> test;

to get the default parameter?

Answer 1

You can’t instantiate a template without angle-brackets, and you can’t give a type the same name as a template, so you can’t do exactly what you want.

You could give the template a different name, and typedef a to the default-sized one.