Question

My password condition is, minimum 8 characters, minimum one special character, minimum one numeric

For this I wrote a simple class to verify, but eventually fails.

Any help is highly appreciated.

public class PasswordVerifier {
    private static final String SPECIAL_CHARACTERS = "(`~!@#$%^&*()_+=-][;'/.,\\<>?|:\"}{)";

    public static void main(String... args) {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        try {
            String password = in.readLine();
            if(!password.matches("^.*(?=.{8,})(?=.*[0-9])(?=.*[SPECIAL_CHARACTERS]).*$")){
                System.out.println("Password does not satisfy compliant");
            } else {
                System.out.println("Yes.. gets through");
            }
        } catch (IOException e) {
            e.printStackTrace();
        }

    }
}

Answer 1

This might work for your requirement:

private static final String SPECIAL_CHARACTERS = "(`~!@#$%^&*()_+=-\\]\\[;'/.,\\<>?|:\"}{)";

public static void main(String[] args) {
    BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
    try {
        String password = in.readLine();
        if(!password.matches("((?=.*\\d)(?=.*["+SPECIAL_CHARACTERS+"]).{8,})")){
            System.out.println("Password does not satisfy compliant");
        } else {
            System.out.println("Yes.. gets through");
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
}

The regex specifies:

• Input must contains one digit from 0-9
• Must contains one special symbols in the list of SPECIAL_CHARACTERS that you’ve defined
• Length should be at least 8 characters