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Home/ Questions/Q 6106907
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T14:07:48+00:00 2026-05-23T14:07:48+00:00

My php code is being displayed in the browser but only after the first

  • 0

My php code is being displayed in the browser but only after the first echo is called leaving this output in the browser

“;
while($row=mysql_fetch_array($results,MYSQL_ASSOC)){
echo ” “.$row[‘title’]; } echo “”; ?>

    <?php
require('settings.php');
?>
<html>
    <head>
        <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js" type="text/javascript"></script>
    </head>
    <body>
    <?php
        $mysql=mysql_connect(mysql_host, mysql_username, mysql_password, true);
        mysql_select_db(mysql_database, $mysql);
        $mostrecent=mysql_query("SELECT * FROM table ORDER BY date DESC", $mysql);
        $top20=mysql_query("SELECT * FROM table", $mysql);
        mysql_close($mysql);
        echo "<div id=\"mostrecent\">";
        while($row=mysql_fetch_array($results,MYSQL_ASSOC)){
            echo "<br />".$row['title'];
        }
        echo "</div>";
    ?>
    </body>
</html>

That is my code and those are constants defined in settings.php using define().

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T14:07:49+00:00Added an answer on May 23, 2026 at 2:07 pm

    ENCODING ERROR, WAS UTF-16 on a server that didn’t support UTF-16, re encoded into UTF-8 works perfectly

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