Question

My php code produce something like that with this link getPower.php?year=2012&country=tr

"Kasan":[[1,50]]
"Tasan":[[1,51],[2,52],[3,52]]
"Hasan":[[1,50]]
"Masan":[[1,51],[2,52],[3,52]]

With this code;

$row = $result->fetch_assoc();

echo json_encode($row['teamName']). ":" ;

putPowerbyTeam($db,$row['teamID'],$year); //End with echo "json_encode($returnArray);"  

echo "\n";

And I’m trayin to convert them into JavaScript Object with this code;

$.ajax({type: "GET",
url: "getPower.php",
data: {year : "year", country : "country"},
success: function(JSONText) {

    var lines = JSONText.split('\n');

    $.each(lines,function(lineNo,line)
                    {
        var mainItems = line.split(':');
        chart.series[lineNo].name = jQuery.parseJSON(eval(mainItems[0]));
        chart.series[lineNo].setData(jQuery.parseJSON(eval(mainItems[1])), true);
    });

},
error: function (xhr, ajaxOptions, thrownError) {
    alert(xhr.status);
    alert(thrownError);
}

I’m an error which say cannot split the null. So, null is returned but i can’t be sure any part of this javascrip code.

So, why null is returned?
What can i do?
Is the rest is good?

Answer 1

Don’t try to build your JSON with multiple echo and json_encode. Use one big associative array and then echo json_encode(array).

Something like this :

$array = array();

$teamName = $row['teamName'];

$array[$teamName] = putPowerbyTeam($db,$row['teamID'],$year); // Return the array instead of doing json_encode($returnArray);

echo json_encode(array);