Question

My preg_replace pattern regex code here..

/<img(.*?)src="(.*?)"/

This is my replace code..

<img$1src="'.$path.'$2"

So i want to negate/exlude a condition..
If img tag have a rel=”customimg”, dont preg_replace so skip it..

Example: Skip This Line

<img rel="customimg" src="http..">

What might add to this regex pattern?

I searched another post, but I couldn’t exactly..

Answer 1

Because src argument may use single or double quotes, I suggest you to use

preg_replace(
  "/(<img\b(?!.*\brel=[\"']customimg[\"']).*?\bsrc=)([\"']).*?\2/i",
  "$1$2" . $path . "$2",
  $string);

Edit:

To add url prefix instead of full url replacement, use

preg_replace(
  "/(<img\b(?!.*\brel=[\"']customimg[\"']).*?\bsrc=)([\"'])(.*?)\2/i",
  "$1$2" . $path . "$3$2",
  $string);