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Home/ Questions/Q 7536811
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T06:40:42+00:00 2026-05-30T06:40:42+00:00

My problem actually seems rather silly… I am writing an iPhone application that uses

  • 0

My problem actually seems rather silly… I am writing an iPhone application that uses MKMapKit. The app grabs the EXIF metadata from a provided geotagged photo. The problem is that the latitude and longitude coordinates that I retrieve, for example:

Lat: 34.25733333333334

Lon: 118.5373333333333

returns a location in China. Is there a regional setting that I am missing or do I need to convert the lat/long coordinates before using them?

Thank you all in advance for any help you can provide.

Here is the code I am using to grab the GPS data. You’ll notice I am logging everything to the console so I can see what the values are:

void (^ALAssetsLibraryAssetForURLResultBlock)(ALAsset *) = ^(ALAsset *asset)
{
    NSDictionary *metadata = asset.defaultRepresentation.metadata;
    NSLog(@"Image Meta Data: %@",metadata);
    NSDictionary *gpsdata = [metadata objectForKey:@"{GPS}"];
    self.lat = [gpsdata valueForKey:@"Latitude"];
    self.lng = [gpsdata valueForKey:@"Longitude"];
    NSLog(@"\nLatitude: %@\nLongitude: %@",self.lat,self.lng);
};

NSURL *assetURL = [mediaInfo objectForKey:UIImagePickerControllerReferenceURL];
ALAssetsLibrary *library = [[ALAssetsLibrary alloc] init];
[library assetForURL:assetURL
         resultBlock:ALAssetsLibraryAssetForURLResultBlock
        failureBlock:^(NSError *error) {
        }];

UIImage *img = [mediaInfo objectForKey:@"UIImagePickerControllerEditedImage"];
previewImage.image = nil;
self.previewImage.image = img;

NSData *imageData = UIImagePNGRepresentation(img);
if ([imageData length] > 0) {
    self._havePictureData = YES;

}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T06:40:43+00:00Added an answer on May 30, 2026 at 6:40 am

    i think you should grab the value using following:

     CLLocation *location = [asset valueForProperty:ALAssetPropertyLocation];
    
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