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Home/ Questions/Q 6830093
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T22:34:39+00:00 2026-05-26T22:34:39+00:00

My problem is about Java / Android : I created a class MyClass which

  • 0

My problem is about Java / Android :

I created a class MyClass which has a method getAllData() that returns an List<MyType> = new ArrayList<MyType>(). In an other class MyOtherClass I call to this method and want to write the returned List into another List<MyType>.

But I get the following error: Unhandled exception type Exception

What can I do about this?

Here’s the code:

MyClass.java

 public List<MyType> datas = new ArrayList<MyType>();

public List<MyType> getAllData() throws Exception{

//add some things to datas... 

return datas;
}

MyOtherClass.java

 public void fetchData(){

    MyClass mydatas = new MyClass();
    List<MyType> thedatas = mydatas.getAllData();

 }

How can I solve the problem?
With an “try / catch(Exception e)” surrounding the statement, it seems not to get the returned List from getAllData();

Thanks a lot in advance!

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  1. Editorial Team
    Editorial Team
    2026-05-26T22:34:39+00:00Added an answer on May 26, 2026 at 10:34 pm

    Since getAllData() might throws a checked exception (i.e., an exception that is not a RunTimeException), you have to surround the statement with try-catch

    public void fetchData() {
        MyClass mydatas = new MyClass();
        try {
            List<MyType> thedatas = mydatas.getAllData();
        } catch (Exception ex) {
            // display or log exception name
        }
    }
    

    Or add throws clause after the method name.

    public void fetchData() throws Exception {
        MyClass mydatas = new MyClass();
        List<MyType> thedatas = mydatas.getAllData();
    }
    
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