Question

My problem is how can I iterate through the command line arguments if the number of allowed arguments is a variable:

example:

./sort.sh n <n integers to sort>
./sort.sh 5 3 4 2 1 5

I tried iterating it through a for-loop and putting it in a .txt file for the sort function but that presents a problem since the delimiter, say i, accepts only constants.

Thanks. 😀

Answer 1

You don’t need the number of arguments. You can get it from within the script with $#.

And you don’t need to loop through the arguments. Just pass them one per line to sort -n.

Something like: printf "%s\n" $@ | sort -n.