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Editorial Team
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Asked: 2026-05-30T21:44:07+00:00

My problem is that I have a PHP that lists images in a folder

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My problem is that I have a PHP that lists images in a folder (and it works fine; that’s not the problem) but I don’t know how to “call” the result in the HTML.

I have this PHP code:

<?php
    $directory="img";
    $dirint = dir($directory);
    while (($archivo = $dirint->read()) !== false)
    {
        if (eregi("gif", $archivo) || eregi("jpg", $archivo) || eregi("png", $archivo)){
            echo '<img src="'.$directory."/".$archivo.'">'."\n";
        }
    }
    $dirint->close();
?>

And in my HTML I have:

<body>
    <div id="gallery">
<img src="photo1.jpg" />
    </div>
    <script>
        Galleria.loadTheme('galleria/themes/classic/galleria.classic.min.js');
        $("#gallery").galleria({

            width: 976,
            height: 350,
            show_imagenav:true
        });
    </script>
</body>

That works great, but I need to replace the <img src="photo1.jpg" /> for the list that PHP creates.

How do I do it?

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1 Answer

  1. Editorial Team

    You mean you want to combine these two examples?

    The HTML file has to be a PHP file or PHP has to parse the *.html or *.htm file. And then you just need to replace your ” with the PHP code snippet so that it becomes:

    <body>
    <div id="gallery">
    <?php
        $directory="img";
        $dirint = dir($directory);
        while (($archivo = $dirint->read()) !== false)
        {
            if (eregi("gif", $archivo) || eregi("jpg", $archivo) || eregi("png", $archivo)){
                echo '<img src="'.$directory."/".$archivo.'">'."\n";
            }
        }
        $dirint->close();
    ?>
    </div>
    <script>
        Galleria.loadTheme('galleria/themes/classic/galleria.classic.min.js');
        $("#gallery").galleria({

            width: 976,
            height: 350,
            show_imagenav:true
        });
    </script>
</body>
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