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Home/ Questions/Q 8795147
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T23:20:52+00:00 2026-06-13T23:20:52+00:00

My problem is that when I move mouse quickly over square element and then

  • 0

My problem is that when I move mouse quickly over square element and then go out with my cursor it sometimes doesn’t finish the “mouseout” part of hover function

My HTML:

<div id="wrapper">
    <div id="o1" class="square"></div>
    <div id="o2" class="square"></div>
</div>

CSS

#wrapper {
    width: 100px;
    height: 100px;
    position: relative;
}
.square {
    width: 100px;
    height: 100px;
    position: absolute;
}
#o1 {
    background: red;
}
#o2 {
    background: blue;
    display:none;
}

Javascript:

$(function(){
    var o1 = $("#o1");
    var o2 = $("#o2");
    $('#wrapper').hover(function() {
        o1.fadeOut(400,function () {
            o2.fadeIn(400);
        });
    }, function() {
        o2.fadeOut(400,function () {
            o1.fadeIn(400);
        });
    });
});

jsFiddle: http://jsfiddle.net/TQ37t/

I have tried using stop() with different parameter on different places in my code but without success. Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T23:20:52+00:00Added an answer on June 13, 2026 at 11:20 pm

    The easiest solution I came up with was to make sure all the queues were stopped before adding any new animations:

    var o1 = $("#o1");
    var o2 = $("#o2");
    $('#wrapper').hover(function() {
        o2.stop(true, true);
        o1.stop(true, true);
        o1.fadeOut(400,function () {
            o2.fadeIn(400);
        });
    }, function() {
        o1.stop(true, true);
        o2.stop(true, true);
        o2.fadeOut(400,function () {
            o1.fadeIn(400);
        });
    });
    

    Note that order matters when stopping the queues. Consider the following sequence:

        o1.fadeOut(400,function () {
            o2.fadeIn(400);
        });
        o2.stop(true, true); // at this point, o1 can still queue a new animation onto o2
            // at this point, o1 might finish fadeOut() and begin o2.fadeIn()
        o1.stop(true, true); // We should have stopped this one first
    
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