Question

My problem is the next, i try to evaluate a list with some vars using a let to asign values to this vars

if i do (def a (list * 'x 'y)) and (let [x 3 y 3] (eval a)) I have a
CompilerException java.lang.RuntimeException: Unable to resolve symbol: x in this context, compiling:(NO_SOURCE_PATH:6)

but if I run
(def x 4) (def y 4) and (eval a) i have a 16, anyway if I run again (let [x 3 y 3] (eval a)) again I have 16,

exist a method to binding the x and y correctly and eval the list?

ty!

Answer 1

Well, you could also eval the let expression, See if this is what you need:

(eval '(let [x 3 y 3] (* x y)))

EDIT :

According to the comments, this will work for your case:

(def a (list (list * 'x 'y)))
(eval (concat '(let [x 3 y 3]) a))

Even better, use quasiquoting:

(def a (list * 'x 'y))
(eval `(let ~'[x 3 y 3] ~a))