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Home/ Questions/Q 9239567
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T08:01:11+00:00 2026-06-18T08:01:11+00:00

My problem is the same than this one . Let’s say I have the

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My problem is the same than this one.

Let’s say I have the following HTML code:

<input type="radio" name="test" id="banana" value="Banana" checked="true" />
<input type="radio" name="test" id="cherry" value="Cherry" />

And the javascript:

$('[type="radio"]').buttonset();

When I click the ‘Cherry’ button, JQuery UI changes the view correctly. However, $('[name="test"]').val(); returns “Banana”…

Any workaround?

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  1. Editorial Team
    Editorial Team
    2026-06-18T08:01:12+00:00Added an answer on June 18, 2026 at 8:01 am

    To solve this problem I called $('[name="test"]:checked').val(); and it seems to work.

    If you want to detect a change of the radio button, do not call $('[name="test"]').click() but $('[name="test"]').change().

    I hope this will help people.

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