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Home/ Questions/Q 683981
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:46:01+00:00 2026-05-14T01:46:01+00:00

My problematic code: testMYSQL=`mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost –skip-column-names –batch -D $mysqlDB -e

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My problematic code:

testMYSQL=`mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost --skip-column-names --batch -D $mysqlDB -e "SELECT $select FROM $mysqlTable WHERE nameTXT='test';"`       

$testMYSQL now contains:

test
test
test

Then I do:

TEST=$(echo $testMYSQL | wc -l)
echo "$TEST"

I would of thought that would work, but it doesn’t, it returns 1

But if I put this into $testMYSQL: “test\ntest\ntest” it will say 3…

Whats going on here? does MYSQL not use new lines?

PS, I know I can use a for loop to loop though the lines then count up the lines that way, but I was hoping for a simpler solution like wc

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:46:01+00:00Added an answer on May 14, 2026 at 1:46 am

    use the $() syntax whenever possible

    $ testMYSQL=$(mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost --skip-column-names --batch -D $mysqlDB -e "SELECT $select FROM $mysqlTable WHERE nameTXT='test';" )
    $ set -- $testMYSQL
    $ echo ${#}
    

    also, if you just want a count of how many nameTXT that is “test”, why not do it in mysql? something like select count($select) from $mysqlTable where nameTXT='tests';

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