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Home/ Questions/Q 6161671
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:31:04+00:00 2026-05-23T21:31:04+00:00

My program basically looks like this: UIViewController -> Custom UIView -> [Array of UIImageView]

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My program basically looks like this:

UIViewController -> Custom UIView -> [Array of UIImageView]

My problem is that my recognizer’s action method is never called. I’ve already set the userInteractionEnabled attribute of my UIImageViews to YES.

On my View Controller’s viewDidLoad:

- (void)viewDidLoad
{
    NSEnumerator *enumerator = [grid.subviews objectEnumerator];
    UIImageView *view;
    UITapGestureRecognizer *recognizer;

    while((view = [enumerator nextObject])){
        recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(openDeal:)];

        view.userInteractionEnabled = YES;
        recognizer.delegate = self;
        recognizer.numberOfTapsRequired = 1;
        [view addGestureRecognizer:recognizer];
        NSLog(@"%d", (int)view.userInteractionEnabled);
        [recognizer release];
    }
    [super viewDidLoad];
}

and openDeal is defined as such:

-(void) openDeal:(UITapGestureRecognizer *) recognizer{
    NSLog(@"%@",[NSString stringWithFormat:@"%d", recognizer.view.tag]);
}
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  1. Editorial Team
    Editorial Team
    2026-05-23T21:31:05+00:00Added an answer on May 23, 2026 at 9:31 pm

    I had the same issue and later found out that I was assigning the same gesture recognizer instance to another view. Gesture recognizers can be associated to a single view only (you can verify that through UIGestureRecognizer’s view property).

    Make sure you are not reusing your recognizers somewhere else in the code.

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