Question

My program currently loops through an array and counts the amount of times a pattern occurs in all of them together.

For example: if I should search “at” at prompt I will end up with:

0,1,2,3,4

But really I want to end up with

4,1

As at appears 4 times in array 1 and once in array 2.

This being the amount of times the pattern occurs in the array.

Any advice on how I can achieve this?

Many thanks in advance!

web = ["cat fat hat mat", "that the who"];

var search = prompt('Search?');

function count(web, pattern)
{
    if (pattern)
    {
        var num = 0;
        var result = [];
        for (i = 0; i < web.length; i++)
        {
            var current = web[i];
            var index = current.indexOf(pattern);
            while (index >= 0)
            {
                result[result.length] = num++;
                index = current.indexOf(pattern, index + 1);
            }
        }
        return result;
    }
    else
    {
        return ("Nothing entered!");
    }
}
alert(count(web, search));

Answer 1

var web = ["cat fat hat mat", "that the who"];

var search = prompt('Search?');

function count(web, pattern)
{
    if (pattern)
    {
        var num = 0;
        var result = [];
        for (i = 0; i < web.length; i++)
        {
            var current = web[i];
            var index = 0;
            do{
                result[i] = num++;
                index = current.indexOf(pattern, index + 1);

            }while (index >= 0)
            num = 0;
        }
        return result;
    }
    else
    {
        return ("Nothing entered!");
    }
}
alert(count(web, search));

This works too

var web = ["cat fat hat mat", "th the who"];

var answer = prompt('Search?');
var search = new RegExp( answer, "g");

function count(web, pattern)
{
    var result = [];
    for(var i=0; i< web.length; i++){
        var matches = web[i].match(search) || [];
        result[i] = matches.length;
    }

    return result.join(",");
}
alert(count(web, search));