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Home/ Questions/Q 7501213
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T20:27:34+00:00 2026-05-29T20:27:34+00:00

My program requires the result from inside an loop to be displayed or outputted

  • 0

My program requires the result from inside an loop to be displayed or outputted with time intervals of 1000ms.
Is it possible to put the timer code:

 int delay2= 1000;
    final Timer timer2 = new Timer();
             timer2.schedule(new TimerTask(){
     public void run(){}

      },delay2, 1000);

Inside a loop to print an answer that is:

 System.out.println("dec2       "+deck2[g]);
       System.out.println("dec1       "+deck1[g]);

Between time intervals of 1000ms?

Thanks For Reading.

EDIT: Will this work?

final Timer timer2 = new Timer();
         timer2.schedule(new TimerTask(){
 public void run(){   
System.out.println("COUNT"+count);
for(int g = 0;g<e+1;g++)
 { 

   System.out.println("dec2       "+deck2[g]);
   System.out.println("dec1       "+deck1[g]);

}
} 
  },delay2, 1000);

EDIT2: Or This?

long t = new Date().getTime(); // time now in millies
do {
    for( g = 0;g<e+1;g++)
    {
    final long now = new Date().getTime();
    if( now - t >= 1000 ) {
System.out.println("dec2       "+deck2[g]);
 System.out.println("dec1       "+deck1[g]);
       t = new Date().getTime();  // reset reference time
    }
}
 count--;   
} while( count==0 );
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T20:27:35+00:00Added an answer on May 29, 2026 at 8:27 pm

    If you don’t mind the performance impact you can do something like this.

    long t = new Date().getTime(); // time now in millies
    do {
        // do something here
        // ...
        final long now = new Date().getTime();
        if( now - t >= 1000 ) {
           // do your logging
           // ...
           t = new Date().getTime();  // reset reference time
        }
    } while( someCondition );
    
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