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Home/ Questions/Q 8072665
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T14:05:27+00:00 2026-06-05T14:05:27+00:00

My query is: result = connection.execute( select id_number from Table where string like ‘_stringStart%’

  • 0

My query is:

result = connection.execute(
         "select id_number from Table where string like '_stringStart%' limit 1;")

gives the error:

query = query % escaped_args
TypeError: not enough arguments for format string

A quick google said to use %% instead of % but that doesn’t work either. How do I escape the % or is there another way to query for a string that starts with a random letter then a certain sequence?

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  1. Editorial Team
    Editorial Team
    2026-06-05T14:05:29+00:00Added an answer on June 5, 2026 at 2:05 pm

    Since this is a literal string, you’re better off using a bound parameter here (illustrated using text()):

    from sqlalchemy import text
    
    connection.execute(
        text("select * from table where "
             "string like :string limit 1"), 
        string="_stringStart%")
    
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