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Home/ Questions/Q 3930782
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T23:17:23+00:00 2026-05-19T23:17:23+00:00

My query: SELECT AVG(time_out – time_in) from time_table Result: 3 days 17:21:21.062313 The problem

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My query:

SELECT AVG(time_out - time_in) from time_table

Result:

3 days 17:21:21.062313

The problem is, the computed average also has the fractional part of a second .062313, which I don’t need, so I must drop it. How do I do that?

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  1. Editorial Team
    Editorial Team
    2026-05-19T23:17:23+00:00Added an answer on May 19, 2026 at 11:17 pm

    date_trunc should do this:

    SELECT date_trunc('second', avg(time_out - time_in))
    FROM time_table
    
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