Question

my question is:
I have a dictionary with one object for each character of the alphabet. Within those objects, there are all values for a specific character.

Example:

alphabetDictionary
  a
    apple
    alien
  b 
   balloon
   ball

I now want to count all entries within this dictionary:

apple
alien
balloon
ball
-> 4

Using this sourcecode only counts the objects (a, b, etc)

NSString *counter = [NSString stringWithFormat:@"Entries (%d)", alphabetDictionary.count];

So how do I get all entries and not the objects a,b,etc?

EDIT 1:
In the viewDidLoad Method I have:

//Initialize the array.
charDict = [[NSMutableDictionary alloc] init];
alphabetArray = [[NSMutableArray alloc] init];

if ([charSpecialArray count] > 0)   {

    //Set object for this character within the dictionary
    [charDict setObject:charSpecialArray forKey:@"#"];
    //fill the alphabetArray with an index value, if this char exists at all
    [alphabetArray addObject:@"#"];
}

if ([charAArray count] > 0) {

    [charDict setObject:charAArray forKey:@"A"];
    [alphabetArray addObject:@"A"];
}

etc.. for each character

followed by:

totalCounter = 0;
//Count all keys within the Dictionary
for (id objectKey in charDict.allKeys) {
    totalCounter += [[charDict objectForKey:objectKey] count];
    NSLog(@"Anzahl: %d", totalCounter);
}   
NSString *counter = [NSString stringWithFormat:@"TXNs (%d)", totalCounter];

self.title = counter;

the results are looking much too high:

• Character H has 33 entries
• the count of H characters results in: 132
• m characters: 1587
• m characters count: 6348

Any ideas why those counts are this high?

Answer 1

The solution to my problem is:
I’ve used NSInteger instead of NSUInteger