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Home/ Questions/Q 8705275
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T03:19:16+00:00 2026-06-13T03:19:16+00:00

My question is related to numerical recipes. I have a global function which computes

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My question is related to numerical recipes.
I have a global function which computes the vector of functions to be minimized

VecDoub vecfunc(VecDoub_I x) {
  // code is here
}

In a class function run, I tried to call the Numerical Recipes function newt, which reads my function vecfunc as shown,

class A {
    void run() {
        VecDoub_IO pt;
        pt.resize(2);
        pt[0] = 0.5;
        pt[1] = 0.5;
        bool check = false;
        newt<VecDoub>(pt, check, &vecfunc);
    }
}

Function newt is declared as

template <class T>
void newt(VecDoub_IO &x, Bool &check, T &vecfunc)

Why do I get the following compiler error?

error C2664: 'newt' : cannot convert parameter 3 from 'VecDoub (__cdecl *)(VecDoub_I)' to 'VecDoub &'
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  1. Editorial Team
    Editorial Team
    2026-06-13T03:19:18+00:00Added an answer on June 13, 2026 at 3:19 am

    In calling newt you explicitly specify that T is VecDoub(You specified newt<VecDoub>) but you pass address of a function to it, so compiler can’t convert your function to VecDoub&. If you want a VecDoub& in newt then call vectfunc and store it in a temporary variable and then pass that variable to the function(since in newt last parameter is a reference to T) but if you really need a function in newt then why you write newt<VecDoub>(pt, check, &vecfunc) while you can write newt(pt, check, &vecfunc) and let C++ deduce the type for you? and beside that in order to receive functions in newt do not get them by reference, instead get them by value, so newt shall be declared as:

    template <class T>
    void newt(VecDoub_IO &x, Bool &check, T vecfunc)
    

    Since functions are usually small objects or pointers this will work and do not decrease performance

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