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Home/ Questions/Q 6953517
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:29:24+00:00 2026-05-27T14:29:24+00:00

My question is very similar to this one , except I’m trying to capture

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My question is very similar to this one, except I’m trying to capture the return code of a ScriptBlock using Invoke-Command (so I can’t use the -FilePath option). Here’s my code:

Invoke-Command -computername $server {\\fileserver\script.cmd $args} -ArgumentList $args
exit $LASTEXITCODE

The problem is that Invoke-Command doesn’t capture the return code of script.cmd, so I have no way of knowing if it failed or not. I need to be able to know if script.cmd failed.

I tried using a New-PSSession as well (which lets me see script.cmd’s return code on the remote server) but I can’t find any way to pass it back to my calling Powershell script to actually DO anything about the failure.

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:29:25+00:00Added an answer on May 27, 2026 at 2:29 pm
    $remotesession = new-pssession -computername localhost
    invoke-command -ScriptBlock { cmd /c exit 2} -Session $remotesession
    $remotelastexitcode = invoke-command -ScriptBlock { $lastexitcode} -Session $remotesession
    $remotelastexitcode # will return 2 in this example
    
    1. Create a new session using new-pssession
    2. Invoke your scripblock in this session
    3. Fetch the lastexitcode from this session
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