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Home/ Questions/Q 6535903
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T10:25:41+00:00 2026-05-25T10:25:41+00:00

My question is very simple, given following piece of code at the beginning var

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My question is very simple, given following piece of code at the beginning

var list = new[] {
    new { name = "lixiang", age = 14 },
    new { name = "lixiang", age = 16 },
    new { name = "lidian", age = 14 }
};
var people = list.GroupBy(x => x.name);

This would give me a compiler error as expected since people is a Group of records:

var x1 = people.Select(x => x.name);

But what I don’t understand is, why this one successfully compile?

var x2 = people.Select(x => x.Select(y => y.name));
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  1. Editorial Team
    Editorial Team
    2026-05-25T10:25:41+00:00Added an answer on May 25, 2026 at 10:25 am

    people is an IEnumerable<IGrouping<string, A'>>, where A' is your anonymous type. IGrouping<string, A'> has no name property, which is why the first select fails.

    However, x in the second example is IGrouping<string, A'>, which inherits IEnumerable<A'>. This makes y typed as A', which does have a name property. This is why the second example compiles fine.

    Note that x2 will have the type IEnumerable<IEnumerable<string>>. To flatten this, change the outer Select to SelectMany:

    var x3 = people.SelectMany(x => x.Select(y => y.name));
    

    In this example, x3 will have the type IEnumerable<string>.

    This is all academic, of course, since people.Select(x => x.name) would be a much faster way to get the same result (assuming that ordering is not significant).

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