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Editorial Team
Asked: May 14, 20262026-05-14T16:59:41+00:00 2026-05-14T16:59:41+00:00

My question is why does the address of an array differ from the address

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My question is why does the address of an array differ from the address of its first position?

I’m trying to write my own malloc, but to start out I’m just allocating a chunk of memory and playing around with the addresses. My code looks roughly like this:

#define BUFF_SIZE 1024
static char *mallocbuff;

int main(){
     mallocbuff = malloc(BUFF_SIZE);
     printf("The address of mallocbuff is %d\n", &mallocbuff);
     printf("The address of mallocbuff[0] is %d\n", &mallocbuff[0]);
}

&mallocbuff is the same address every time I run it. &mallocbuff[0] is some random address every time. I was expecting the addresses to match each other. Can anyone explain why this isn’t the case?

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  1. Editorial Team
    Editorial Team
    2026-05-14T16:59:42+00:00Added an answer on May 14, 2026 at 4:59 pm

    &mallocbuff is the address of the named variable mallocbuff. &mallocbuff[0] is the address of the first element in the buffer pointed to by mallocbuff, that you allocated with malloc().

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