Question

My sample table data is:

and my sql query is:

SELECT
Distinct
   CASE CHARINDEX( '?', SessionURL)
       WHEN 0 THEN SessionURL
       ELSE LEFT(SessionURL, CHARINDEX( '?', SessionURL) - 1) END AS VisitPage, count(*) as [VisitTime] 
FROM SessionTracker  
 group by SessionURL
order by [VisitTime] desc

Query run sucessfully and returns a value with out query string.Means result from above data is:

But I want a result only in a format:

Default
Modules

Is it possible this type of filter in sql query.If yes suggest a way.Thanks.

Answer 1

Yes. The same way as you filter the querystring, filter on the / and the . You need the SUBSTRING function. To find the last occurence of the /, use the REVERSE function.

ie.

select pagename, COUNT(*)
from
(
    select 
        reverse(case CHARINDEX('/', withoutsuf) when 0 then withoutsuf 
        else LEFT(withoutsuf,CHARINDEX('/', withoutsuf)-1 ) end) as pagename
    from
    (
        select 
            substring(withoutq, CHARINDEX('.', withoutq)+1, LEN(withoutq)) withoutsuf
        from
        (
            select
                REVERSE(
                    CASE CHARINDEX( '?', SessionURL) 
                    WHEN 0 THEN SessionURL 
                    ELSE LEFT(SessionURL, CHARINDEX( '?', SessionURL) - 1) END) as withoutq
            from SessionTracker
        ) v
    ) v
) v
group by pagename