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Home/ Questions/Q 8963985
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T16:28:57+00:00 2026-06-15T16:28:57+00:00

My script creates files to export by concatenating a file path with a file

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My script creates files to export by concatenating a file path with a file type suffix. For example,

int = 3
print r"C:\Test\\" + str(int) + ".jpg"

This returns C:\Test\\3.jpg

I thought that because I included the ‘r’ at the beginning, I wouldn’t need a double backslash at the end, because it’d be treated as a raw string. But the following doesn’t work:

int = 3
print r"C:\Test\" + str(int) + ".jpg"

…presumably because Python is seeing an escape character before the end quote. So what’s the point of the ‘r’ then? And while my files get saved in the right place when exported, I don’t like that the print command gives me two backslashes after Test (eg C:\Test\3.jpg) when it just gives me one after C:

How can I get a single backslash in my file paths please?

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  1. Editorial Team
    Editorial Team
    2026-06-15T16:28:58+00:00Added an answer on June 15, 2026 at 4:28 pm

    Don’t try and use string manipulation to build up file paths. Python has the os.path module for that:

    import os.path
    i = 3
    print os.path.join("C:\Test", str(i) + ".jpg")
    

    This will ensure the path is constructed properly.

    (Also, don’t call an integer int, as it shadows the built-in int() function.)

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