Question

My SQL query returns results with 4 columns “A”, “B”, “C”, “D”.

Suppose the results are:

A    B    C    D
1    1    1    1
1    1    1    2
2    2    2    1

Is it possible to get the count of duplicate rows with columns “A”, “B”, “C” in each row.

e.g. the expected result is:

A    B    C    D    cnt
1    1    1    1    2
1    1    1    2    2
2    2    2    1    1

I tried using count(*) over. But it returns me the total number of rows returned by the query.
Another information is that in example I have mentioned only 3 columns based on which I need to check the count. But my actual query has such 8 columns. And number of rows in database are huge. So I think group by will not be a feasible option here.
Any hint is appreciable.
Thanks.

Answer 1

Maybe too late, but probably the count over as analytic function (aka window function) within oracle helps you. When I understand your request correctly, this should solve your problem :

create table sne_test(a number(1)
                 ,b number(1)
                 ,c number(1)
                 ,d number(1)
                 ,e number(1)
                 ,f number(1));

insert into sne_test values(1,1,1,1,1,1);
insert into sne_test values(1,1,2,1,1,1);
insert into sne_test values(1,1,2,4,1,1);
insert into sne_test values(1,1,2,5,1,1);
insert into sne_test values(1,2,1,1,3,1);
insert into sne_test values(1,2,1,2,1,2);
insert into sne_test values(2,1,1,1,1,1);

commit;

 SELECT a,b,c,d,e,f, 
       count(*) over (PARTITION BY a,b,c)
  FROM sne_test;

 A  B  C  D  E  F AMOUNT
-- -- -- -- -- -- ------
 1  1  1  1  1  1      1
 1  1  2  4  1  1      3
 1  1  2  1  1  1      3
 1  1  2  5  1  1      3
 1  2  1  1  3  1      2
 1  2  1  2  1  2      2
 2  1  1  1  1  1      1