Question

My Start() has some really slow serial code so I figure i’ll throw it into a task and await it.

await new Task(() => { c.Start(); });

This compiles however it appears it doesn’t run the task unless i call Start(). Now instead of the simple one liner I have 3 lines. Is there a way I can write the below in one line?

var t = new Task(() => { c.Start(); });
t.Start();
await t;

Answer 1

You’re looking for await Task.Run(c.Start). If you’re on .NET 4.0 (rather than 4.5), you can use await Task.Factory.StartNew(c.Start).

Prefer Task.Factory.StartNew to manually constructing/starting a Task, and Task.Run to Task.Factory.StartNew. Each one uses a more optimal implementation, and is not simply shorthand.