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Home/ Questions/Q 7763093
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T14:34:43+00:00 2026-06-01T14:34:43+00:00

my string is: [{property:surname,direction:ASC}] can I get GSON to deserialise this, without adding to

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my string is:

"[{"property":"surname","direction":"ASC"}]"

can I get GSON to deserialise this, without adding to it / wrapping it?
Basically, I need to deserialise an array of name-value pairs.
I’ve tried a few approaches, to no avail.

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  1. Editorial Team
    Editorial Team
    2026-06-01T14:34:44+00:00Added an answer on June 1, 2026 at 2:34 pm

    You basically want to represent it as List of Maps:

    public static void main( String[] args )
    {
        String json = "[{\"property\":\"surname\",\"direction\":\"ASC\"}]";
    
        Type listType = new TypeToken<ArrayList<HashMap<String,String>>>(){}.getType();
    
        Gson gson = new Gson();
    
        ArrayList<Map<String,String>> myList = gson.fromJson(json, listType);
    
        for (Map<String,String> m : myList)
        {
            System.out.println(m.get("property"));
        }
    }
    

    Output:

    surname

    If the objects in your array contain a known set of key/value pairs, you can create a POJO and map to that:

    public class App 
    {
        public static void main( String[] args )
        {
            String json = "[{\"property\":\"surname\",\"direction\":\"ASC\"}]";
            Type listType = new TypeToken<ArrayList<Pair>>(){}.getType();
            Gson gson = new Gson();
            ArrayList<Pair> myList = gson.fromJson(json, listType);
    
            for (Pair p : myList)
            {
                System.out.println(p.getProperty());
            }   
        }
    }
    
    class Pair
    {
        private String property;
        private String direction;
    
        public String getProperty() 
        {
            return property;
        }    
    }
    
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