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Home/ Questions/Q 7740191
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T08:42:52+00:00 2026-06-01T08:42:52+00:00

My table looks like this (and I’m using MySQL): m_id | v_id | timestamp

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My table looks like this (and I’m using MySQL):

m_id | v_id | timestamp
------------------------
6    |   1  | 1333635317
34   |   1  | 1333635323
34   |   1  | 1333635336
6    |   1  | 1333635343
6    |   1  | 1333635349

My target is to take each m_id one time, and order by the highest timestamp.

The result should be:

m_id | v_id | timestamp
------------------------
6    |   1  | 1333635349
34   |   1  | 1333635336

And i wrote this query:

SELECT * FROM table GROUP BY m_id ORDER BY timestamp DESC

But, the results are:

m_id | v_id | timestamp
------------------------
34   |   1  | 1333635323
6    |   1  | 1333635317

I think it causes because it first does GROUP_BY and then ORDER the results.

Any ideas? Thank you.

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  1. Editorial Team
    Editorial Team
    2026-06-01T08:42:53+00:00Added an answer on June 1, 2026 at 8:42 am

    One way to do this that correctly uses group by:

    select l.* 
    from table l
    inner join (
      select 
        m_id, max(timestamp) as latest 
      from table 
      group by m_id
    ) r
      on l.timestamp = r.latest and l.m_id = r.m_id
    order by timestamp desc
    

    How this works:

    • selects the latest timestamp for each distinct m_id in the subquery
    • only selects rows from table that match a row from the subquery (this operation — where a join is performed, but no columns are selected from the second table, it’s just used as a filter — is known as a “semijoin” in case you were curious)
    • orders the rows
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