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Home/ Questions/Q 6930073
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:24:00+00:00 2026-05-27T11:24:00+00:00

My TableX has reference to TableY. @JoinColumn(name = idTableY, referencedColumnName = idTableY) @ManyToOne(optional =

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My TableX has reference to TableY.

@JoinColumn(name = "idTableY", referencedColumnName = "idTableY")
@ManyToOne(optional = false, fetch=FetchType.LAZY)
private TableY idTableY; 

and I get this error.

<openjpa-2.0.0-r422266:935683 fatal user error> org.apache.openjpa.persistence.ArgumentException 
"com.mycompany.entities.TableX.idTableY" has columns with targets, but OpenJPA does not support any joins on this mapping in this context.

Table Y has this code:

 @OneToMany(cascade = CascadeType.ALL, mappedBy = "idTableY")
    private Collection<TableX> tableXCollection;

This generated eclipse-link code is 100% normal ( all other entities/tables with similar code have no problems).

But a couple of these are giving such errors. Any idea why?

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:24:01+00:00Added an answer on May 27, 2026 at 11:24 am

    Try to remove the @JoinColumn definition it is unnecessary. The join column containing foreign key is generated automatically. Entity is not a table those are two different things. Entity is class mapped on db table(s).

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