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Home/ Questions/Q 4045328
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T13:24:42+00:00 2026-05-20T13:24:42+00:00

my this ajax code snipped is working fine, hut how can i display a

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my this ajax code snipped is working fine, hut how can i display a loading image in a div. in the same scenario.

$.ajax({
         url:'ajax_image_refresher.php?'+$('#frm_text').serialize(),
         method:'get',
         success:function(data){
         if(data =='') return;
         img_tag = '';
         $('#wapal').html(img_tag);
       }
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  1. Editorial Team
    Editorial Team
    2026-05-20T13:24:43+00:00Added an answer on May 20, 2026 at 1:24 pm
    <div id="displayStatus"></div>
    
    jQuery('#displayStatus').html('Loading');
    
    jQuery.ajax({
        //options
        success:function()
        {
           //your codes
           jQuery('#displayStatus').html('Loaded').delay(2000).fadeOut();
        }
    });
    
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