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Home/ Questions/Q 1107635
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:57:57+00:00 2026-05-17T01:57:57+00:00

My thoughts at first were that this was a syntax problem, but I don’t

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My thoughts at first were that this was a syntax problem, but I don’t see any syntax issues. I’ve added debug code and that gave odd results, x is logged before jQuery('#notification')

document.triggerNotification = function (type, message) {
    jQuery(document.body).append("<div class='push-notification push-"+type+"' id='notification'>"+message+"</div>");

    setTimeout(jQuery('#notification').fadeOut(1200, function () {
        console.log(jQuery('#notification'));
        jQuery('#notification').remove();
        console.log(jQuery('#notification'));
    }), 3000);
    console.log('x');
}

Firebug provides the following output:

x
[div#notification.push-notification]
[]
missing ] after element list - [Break on this error] [object Object]

Everything is successfully executing but it’s still throwing an error.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T01:57:58+00:00Added an answer on May 17, 2026 at 1:57 am

    setTimeout expects a function as its first argument. You’re giving it a collection of jQuery objects. Try the following:

    document.triggerNotification = function (type, message) {
        jQuery(document.body).append("<div class='push-notification push-"+type+"' id='notification'>"+message+"</div>");
    
        setTimeout(function() { jQuery('#notification').fadeOut(1200, function () {
            console.log(jQuery('#notification'));
            jQuery('#notification').remove();
            console.log(jQuery('#notification'));
        })}, 3000);
        console.log('x');
    }
    

    Note the anonymous function that has been wrapped around your jQuery('#notification').fadeOut() call. With your current code, I’d expect the fadeOut to execute immediately, instead of after the specified 3 seconds.

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