Question

My Tornado app receive the image in headers. So, I want to re-size it and store it. But I have trouble with opening image – to create PIL object I must have the file with image and pass the name of file to open() method of Image module of PIL. But I only have headers and file info there. Should I create temp file to create Image object? Or maybe some other solutions?

class ImageHandler(BaseHandler):
    def post(self):
        f = open("out.jpg", "w")
        im = Image.open(self.request.files["ImageUpload"][0]["body"])
        im.save(f, "JPEG")
        self.finish()

TIA!

UPD1 (@bernie)

Traceback (most recent call last):
  File "/usr/local/lib/python2.7/site-packages/tornado-2.2-py2.7.egg/tornado/web.py", line 988, in _execute
    getattr(self, self.request.method.lower())(*args, **kwargs)
  File "server.py", line 160, in post
    im = Image.open(StringIO(self.request.files["ImageUpload"][0]["body"]))
TypeError: 'module' object is not callable

Answer 1

PIL documentation states that we can provide a file name or a file-like object to open().
So we can use StringIO to provide PIL a file-like object.
Example applied to your code:

from PIL import Image
from io import StringIO

im = Image.open(StringIO(self.request.files["ImageUpload"][0]["body"]))
im.save("out.jpg", "JPEG")