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Home/ Questions/Q 713179
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:55:56+00:00 2026-05-14T04:55:56+00:00

My two tables look like this: TABLE1 TABLE2 +——————–+ +——————–+ |field1|field2|field3| and |field2|field4|field5| +——————–+

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My two tables look like this:

       TABLE1                      TABLE2
+--------------------+      +--------------------+
|field1|field2|field3|  and |field2|field4|field5|
+--------------------+      +--------------------+

I am already running a SELECT query for TABLE1, and assorting all of the data into variables:

$query = "SELECT * FROM TABLE1 WHERE field2 = 2";
$result = mysql_query($query);
$num_rows = mysql_num_rows($result);    
  if((!is_bool($result) || $result) && $num_rows) {
   while($row = mysql_fetch_array($result))
    {
   $field1 = $row['field1'];
   $field2 = $row['field2'];
   $field3 = $row['field3'];
    }
  }

What I want to do is get the data from ‘field4’ on TABLE2 and add it to my variables. I would want to get field4 WHERE field2 = 2

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:55:56+00:00Added an answer on May 14, 2026 at 4:55 am
    SELECT
      t1.*,
      t2.field4
    FROM
      TABLE1 AS t1,
      TABLE2 AS t2
    WHERE 
        t1.field2 = 2
      AND
        t1.field2 = t2.field2
    

    You want to join the two table which can be done explicitly (using the JOIN operator or one of its variants) our implicitly (by SELECTing from multiple tables directly).

    From your description, I suppose that you want to do the join where field2 in the two tables have the same value (2).


    If TABLE2 will not always provide a valid join candidate but you still want the data from TABLE1, you should use a LEFT JOIN (giving NULL for field4 where nothing matched):

    SELECT
      t1.*,
      t2.field4
    FROM
        TABLE1 AS t1
      LEFT JOIN
        TABLE2 AS t2
      ON
        t1.field2 = t2.field2
    WHERE 
      t1.field2 = 2
    
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