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Home/ Questions/Q 214533
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T18:23:01+00:00 2026-05-11T18:23:01+00:00

My understanding is that Java’s implementation of regular expressions is based on Perl’s. However,

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My understanding is that Java’s implementation of regular expressions is based on Perl’s. However, in the following example, if I execute the same regex with the same string, Java and Perl return different results.

Here’s the Java example:

public class RegexTest {
    public static void main( String args[] ) {
        String sentence = "This is a test of regular expressions.";
        System.out.println( sentence.matches( "\\w" ) ? "Matches" : "Doesn't match" );
    }
}

This returns: Doesn’t match

Here’s the Perl example:

my $sentence = 'This is a test of regular expressions.';
print ( $sentence =~ /\w/ ? "Matches" : "Doesn't match" ) . "\n";

This returns: Matches

To me, the Perl result makes sense. It looks for a match for a single word character. I don’t understand why Java doesn’t consider it a match. What’s the reason for the difference?

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  1. Editorial Team
    Editorial Team
    2026-05-11T18:23:01+00:00Added an answer on May 11, 2026 at 6:23 pm

    The Java matches method is testing whether the regex matches the entire String. To test whether a regex can be found anywhere in a string, create a Matcher and use its find method.

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