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Home/ Questions/Q 7413373
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T06:41:06+00:00 2026-05-29T06:41:06+00:00

My upload method as below: private void upload(String Server, String FilePath, String SavePath, String

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My upload method as below:

private void upload(String Server, String FilePath, String SavePath, String NewName) {
String end = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
try {
URL url = new URL(ActionUrl);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setDoInput(true);
con.setDoOutput(true);
con.setUseCaches(false);
con.setRequestMethod("POST");
con.setRequestProperty("Connection", "Keep-Alive");
con.setRequestProperty("Accept", "text/*");
con.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
ds = new DataOutputStream(con.getOutputStream());
ds.writeBytes(twoHyphens + boundary + end);
ds.writeBytes("Content-Disposition: form-data;" + "name=\"folder\"" + end + end);
ds.write(SavePath.getBytes("UTF-8"));
ds.writeBytes(end);
ds.writeBytes(twoHyphens + boundary + end);
ds.writeBytes("Content-Disposition: form-data;" + "name=\"Filedata\"; filename=\"");
ds.write(NewName.getBytes("UTF-8"));
ds.writeBytes("\"" + end);
ds.writeBytes(end);

FileInputStream fStream = new FileInputStream(uploadFile);
int bufferSize = 1024;
byte[] buffer = new byte[bufferSize];
int length = -1;
while((length = fStream.read(buffer)) != -1) {
ds.write(buffer, 0, length);
}       
ds.writeBytes(end);
ds.writeBytes(twoHyphens + boundary + twoHyphens + end);

fStream.close();
ds.flush();
InputStream is = con.getInputStream();
int ch;
StringBuffer b = new StringBuffer();
while((ch = is.read()) != -1) {
b.append((char)ch);
}
System.out.println("UPLOAD" + "SUCCESS");
ds.close();
}
catch(Exception e) {
e.printStackTrace();
}
}

I found the line InputStream is = con.getInputStream(); spend most time.
But how to get the progress of it send?
Or how to modify my method to upload file “by parts”?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T06:41:07+00:00Added an answer on May 29, 2026 at 6:41 am

    You can try following code,

    First display a Progress Dialog Before calling your upload method,

    progDailog = ProgressDialog.show(loginAct,"Process ", "please wait....",true,true);
    
    new Thread ( new Runnable()
    {
         public void run()
         {
          // your uploading code goes here
         }
    }).start();
    
     Handler progressHandler = new Handler() 
     {
    
         public void handleMessage(Message msg1) 
         {
    
             progDailog.dismiss();
             }
     }
    
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