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Home/ Questions/Q 8711533
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T04:54:04+00:00 2026-06-13T04:54:04+00:00

my_list = [‘apple’, ‘pear’, ‘orange’, ‘raspberry’] # I know that I’m always looking for

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my_list = ['apple', 'pear', 'orange', 'raspberry']

# I know that I'm always looking for pear.
print 'pear' in my_list # prints True

# I want to be able to get a key by its value.
pear_key = my_list['pear'].key # should be 1

# Print the next item in the list.
print my_list[pear_key + 1] # should print orange

I know that pear will always be an item in my list (not the position though), and I’m looking for a way to get the value of the next item in that list, either by getting the current key by knowing its value and advancing it by one (like I did in the example above) or by using something like my_list.next.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T04:54:05+00:00Added an answer on June 13, 2026 at 4:54 am
    try:
        pos = my_list.index('pear')
        print my_list[pos + 1]
        # orange
    except IndexError as e:
        pass # original value didn't exist or was end of list, so what's +1 mean?
    

    You could of course pre-cache it, by using (think it’s probably the itertools pair recipe)

    from itertools import tee
    fst, snd = tee(iter(my_list))
    next(snd, None)
    d = dict(zip(fst, snd))
    

    But then you lose the fact of whether it was in the original list, or just didn’t have a logical next value.

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