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Home/ Questions/Q 8150481
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T15:04:28+00:00 2026-06-06T15:04:28+00:00

MyCode $query = mysql_query(SELECT COUNT(`op_id`) FROM `room_group_options` WHERE `group` = ‘$group’); echo $query; $result

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MyCode

$query = mysql_query("SELECT COUNT(`op_id`) FROM `room_group_options` WHERE `group` = '$group'");
echo $query;
$result = mysql_result($query, 0) ==  1) ? true : false;
if($result === true)
{
$error = 'already have this data';
}    

My code for checking already have data yet?, the problem is after run this code is the result always false, then I have try to echo $query and I got Resource id #11

How can I fix this problem?

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  1. Editorial Team
    Editorial Team
    2026-06-06T15:04:28+00:00Added an answer on June 6, 2026 at 3:04 pm

    mysql_query return a resource

    and also change the condition as mysql_result return false on failure

    so condition should be like this

    $result = (FALSE !== mysql_result($query, 0)) ? TRUE : FALSE;
    

    if you want to fetch from resource link so call

    while ( $row = mysql_fetch_assoc($query))
    {
      $fetch[]= $row;
    }
    
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