Question

MySQL

`field1` tinyint(1) NOT NULL default '1',
`field2` tinyint(1) NOT NULL default '1',
`field3` tinyint(1) NOT NULL default '1',
`field4` tinyint(1) NOT NULL default '1',
`field5` tinyint(1) NOT NULL default '1',

HTML

<form method="post">
<input type="hidden" name="blah" value="blah">

<input type="checkbox" name="field1" value="1">
<input type="checkbox" name="field2" value="1">
<input type="checkbox" name="field3" value="1">
<input type="checkbox" name="field4" value="1">
<input type="checkbox" name="field5" value="1">

<button type="submit">Submit</button>

</form>

PHP

mysql_query("UPDATE `table` SET `field1` = '$_POST[field1]', .......");

So, what I want to do is:

a) If the checkbox is checked, I want to update the appropriate field with 1

b) If the checkbox is unchecked, I want to update the field with 0

And now, please tell me I don’t have to do it like this and that there is a nicer way of doing it:

$field1 = isset($_POST['field1']) ? 1 : 0;
$field2 = isset($_POST['field2']) ? 1 : 0;
$field3 = isset($_POST['field3']) ? 1 : 0;
$field4 = isset($_POST['field4']) ? 1 : 0;
$field5 = isset($_POST['field5']) ? 1 : 0;

mysql_query("UPDATE `table` SET `field1` = '$field1', `field2` = '$field2' ....");

Answer 1

You can use field[]

<input type="checkbox" name="field[0]" value="1">
<input type="checkbox" name="field[1]" value="1">

So you can do a simple loop:

for($i=0;$i<5;$i++)
   $field[$i] = isset($_POST['field'][$i]) ? 1 : 0;

And then build your SQL

If you want to skip the isset Part you could use a radio type, so You have always or the 1 value or 0 value setted.